4(2x-3)^3-(2x-3)(4x^2-6x+9)=18x-3

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Solution for 4(2x-3)^3-(2x-3)(4x^2-6x+9)=18x-3 equation: 



4(2x-3)^3-(2x-3)(4x^2-6x+9)=18x-3

We move all terms to the left:

4(2x-3)^3-(2x-3)(4x^2-6x+9)-(18x-3)=0

We get rid of parentheses

4(2x-3)^3-(2x-3)(4x^2-6x+9)-18x+3=0

We add all the numbers together, and all the variables

-18x+4(2x-3)^3-(2x-3)(4x^2-6x+9)+3=0

We move all terms containing x to the left, all other terms to the right

-18x+4(2x-3)^3-(2x-3)(4x^2-6x+9)=-3

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